110 lines
		
	
	
		
			3.3 KiB
		
	
	
	
		
			C
		
	
	
	
			
		
		
	
	
			110 lines
		
	
	
		
			3.3 KiB
		
	
	
	
		
			C
		
	
	
	
| /*
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| FUNCTION
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| <<lldiv>>---divide two long long integers
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| 
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| INDEX
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|         lldiv
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| 
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| SYNOPSIS
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|         #include <stdlib.h>
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|         lldiv_t lldiv(long long <[n]>, long long <[d]>);
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| 
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| DESCRIPTION
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| Divide
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| @tex
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| $n/d$,
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| @end tex
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| @ifnottex
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| <[n]>/<[d]>,
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| @end ifnottex
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| returning quotient and remainder as two long long integers in a structure 
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| <<lldiv_t>>.
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| 
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| RETURNS
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| The result is represented with the structure
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| 
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| . typedef struct
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| . {
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| .  long long quot;
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| .  long long rem;
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| . } lldiv_t;
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| 
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| where the <<quot>> field represents the quotient, and <<rem>> the
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| remainder.  For nonzero <[d]>, if `<<<[r]> = ldiv(<[n]>,<[d]>);>>' then
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| <[n]> equals `<<<[r]>.rem + <[d]>*<[r]>.quot>>'.
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| 
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| To divide <<long>> rather than <<long long>> values, use the similar
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| function <<ldiv>>.
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| 
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| PORTABILITY
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| <<lldiv>> is ISO 9899 (C99) compatable.
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| 
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| No supporting OS subroutines are required.
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| */
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| 
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| /*-
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|  * Copyright (c) 2001 Mike Barcroft <mike@FreeBSD.org>
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|  * All rights reserved.
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|  *
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|  * Redistribution and use in source and binary forms, with or without
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|  * modification, are permitted provided that the following conditions
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|  * are met:
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|  * 1. Redistributions of source code must retain the above copyright
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|  *    notice, this list of conditions and the following disclaimer.
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|  * 2. Redistributions in binary form must reproduce the above copyright
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|  *    notice, this list of conditions and the following disclaimer in the
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|  *    documentation and/or other materials provided with the distribution.
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|  *
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|  * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
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|  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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|  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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|  * ARE DISCLAIMED.  IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
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|  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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|  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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|  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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|  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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|  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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|  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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|  * SUCH DAMAGE.
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|  */
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| 
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| #include <stdlib.h>
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| 
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| /*
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|  * The ANSI standard says that |r.quot| <= |n/d|, where
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|  * n/d is to be computed in infinite precision.  In other
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|  * words, we should always truncate the quotient towards
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|  * 0, never -infinity.
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|  *
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|  * Machine division and remainer may work either way when
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|  * one or both of n or d is negative.  If only one is
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|  * negative and r.quot has been truncated towards -inf,
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|  * r.rem will have the same sign as denom and the opposite
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|  * sign of num; if both are negative and r.quot has been
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|  * truncated towards -inf, r.rem will be positive (will
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|  * have the opposite sign of num).  These are considered
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|  * `wrong'.
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|  *
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|  * If both are num and denom are positive, r will always
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|  * be positive.
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|  *
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|  * This all boils down to:
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|  *      if num >= 0, but r.rem < 0, we got the wrong answer.
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|  * In that case, to get the right answer, add 1 to r.quot and
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|  * subtract denom from r.rem.
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|  */
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| lldiv_t
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| lldiv (long long numer, long long denom)
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| {
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| 	lldiv_t retval;
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| 
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| 	retval.quot = numer / denom;
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| 	retval.rem = numer % denom;
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| 	if (numer >= 0 && retval.rem < 0) {
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| 		retval.quot++;
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| 		retval.rem -= denom;
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| 	}
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| 	return (retval);
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| }
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| 
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